Author: Divyashree Sreepathihalli
Date created: 2023/10/23
Last modified: 2023/10/30
Description: Instructions & troubleshooting for migrating your Keras 2 code to multi-backend Keras 3.
This guide will help you migrate TensorFlow-only Keras 2 code to multi-backend Keras 3 code. The overhead for the migration is minimal. Once you have migrated, you can run Keras workflows on top of either JAX, TensorFlow, or PyTorch.
This guide has two parts:
Let's get started.
First, lets install keras-nightly
.
This example uses the TensorFlow backend (os.environ["KERAS_BACKEND"] = "tensorflow"
).
After you've migrated your code, you can change the "tensorflow"
string to "jax"
or "torch"
and click "Restart runtime" in Colab, and your code will run on the JAX or PyTorch backend.
!pip install -q keras-nightly
import os
os.environ["KERAS_BACKEND"] = "tensorflow"
import keras
import tensorflow as tf
import numpy as np
[[34;49mnotice[1;39;49m][39;49m A new release of pip is available: [31;49m23.3.1[39;49m -> [32;49m24.0
[[34;49mnotice[1;39;49m][39;49m To update, run: [32;49mpip install --upgrade pip
First, replace your imports:
from tensorflow import keras
to import keras
from tensorflow.keras import xyz
(e.g. from tensorflow.keras import layers
)
to from keras import xyz
(e.g. from keras import layers
)tf.keras.*
to keras.*
Next, start running your tests. Most of the time, your code will execute on Keras 3 just fine. All issues you might encounter are detailed below, with their fixes.
jit_compile
is set to True
by default on GPU.The default value of the jit_compile
argument to the Model
constructor has been set to
True
on GPU in Keras 3. This means that models will be compiled with Just-In-Time (JIT)
compilation by default on GPU.
JIT compilation can improve the performance of some models. However, it may not work with
all TensorFlow operations. If you are using a custom model or layer and you see an
XLA-related error, you may need to set the jit_compile
argument to False
. Here is a list
of known issues encountered when
using XLA with TensorFlow. In addition to these issues, there are some
ops that are not supported by XLA.
The error message you could encounter would be as follows:
Detected unsupported operations when trying to compile graph
__inference_one_step_on_data_125[] on XLA_GPU_JIT
For example, the following snippet of code will reproduce the above error:
class MyModel(keras.Model):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
def call(self, inputs):
string_input = tf.strings.as_string(inputs)
return tf.strings.to_number(string_input)
subclass_model = MyModel()
x_train = np.array([[1, 2, 3], [4, 5, 6]])
subclass_model.compile(optimizer="sgd", loss="mse")
subclass_model.predict(x_train)
How to fix it: set jit_compile=False
in model.compile(..., jit_compile=False)
,
or set the jit_compile
attribute to False
, like this:
class MyModel(keras.Model):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
def call(self, inputs):
# tf.strings ops aren't support by XLA
string_input = tf.strings.as_string(inputs)
return tf.strings.to_number(string_input)
subclass_model = MyModel()
x_train = np.array([[1, 2, 3], [4, 5, 6]])
subclass_model.jit_compile = False
subclass_model.predict(x_train)
1/1 ━━━━━━━━━━━━━━━━━━━━ 0s 51ms/step
array([[1., 2., 3.],
[4., 5., 6.]], dtype=float32)
Saving to the TF SavedModel format via model.save()
is no longer supported in Keras 3.
The error message you could encounter would be as follows:
>>> model.save("mymodel")
ValueError: Invalid filepath extension for saving. Please add either a `.keras` extension
for the native Keras format (recommended) or a `.h5` extension. Use
`model.export(filepath)` if you want to export a SavedModel for use with
TFLite/TFServing/etc. Received: filepath=saved_model.
The following snippet of code will reproduce the above error:
sequential_model = keras.Sequential([
keras.layers.Dense(2)
])
sequential_model.save("saved_model")
How to fix it: use model.export(filepath)
instead of model.save(filepath)
sequential_model = keras.Sequential([keras.layers.Dense(2)])
sequential_model(np.random.rand(3, 5))
sequential_model.export("saved_model")
INFO:tensorflow:Assets written to: saved_model/assets
INFO:tensorflow:Assets written to: saved_model/assets
Saved artifact at 'saved_model'. The following endpoints are available:
* Endpoint 'serve'
args_0 (POSITIONAL_ONLY): TensorSpec(shape=(3, 5), dtype=tf.float32, name='keras_tensor')
Output Type:
TensorSpec(shape=(3, 2), dtype=tf.float32, name=None)
Captures:
14428321600: TensorSpec(shape=(), dtype=tf.resource, name=None)
14439128528: TensorSpec(shape=(), dtype=tf.resource, name=None)
Loading a TF SavedModel file via keras.models.load_model()
is no longer supported
If you try to use keras.models.load_model()
with a TF SavedModel, you will get the following error:
ValueError: File format not supported: filepath=saved_model. Keras 3 only supports V3
`.keras` files and legacy H5 format files (`.h5` extension). Note that the legacy
SavedModel format is not supported by `load_model()` in Keras 3. In order to reload a
TensorFlow SavedModel as an inference-only layer in Keras 3, use
`keras.layers.TFSMLayer(saved_model, call_endpoint='serving_default')` (note that your
`call_endpoint` might have a different name).
The following snippet of code will reproduce the above error:
keras.models.load_model("saved_model")
How to fix it: Use keras.layers.TFSMLayer(filepath, call_endpoint="serving_default")
to reload a TF
SavedModel as a Keras layer. This is not limited to SavedModels that originate from Keras – it will work
with any SavedModel, e.g. TF-Hub models.
keras.layers.TFSMLayer("saved_model", call_endpoint="serving_default")
<TFSMLayer name=tfsm_layer, built=True>
Model()
can no longer be passed deeply nested inputs/outputs (nested more than 1 level
deep, e.g. lists of lists of tensors).
You would encounter errors as follows:
ValueError: When providing `inputs` as a dict, all values in the dict must be
KerasTensors. Received: inputs={'foo': <KerasTensor shape=(None, 1), dtype=float32,
sparse=None, name=foo>, 'bar': {'baz': <KerasTensor shape=(None, 1), dtype=float32,
sparse=None, name=bar>}} including invalid value {'baz': <KerasTensor shape=(None, 1),
dtype=float32, sparse=None, name=bar>} of type <class 'dict'>
The following snippet of code will reproduce the above error:
inputs = {
"foo": keras.Input(shape=(1,), name="foo"),
"bar": {
"baz": keras.Input(shape=(1,), name="bar"),
},
}
outputs = inputs["foo"] + inputs["bar"]["baz"]
keras.Model(inputs, outputs)
How to fix it: replace nested input with either dicts, lists, and tuples of input tensors.
inputs = {
"foo": keras.Input(shape=(1,), name="foo"),
"bar": keras.Input(shape=(1,), name="bar"),
}
outputs = inputs["foo"] + inputs["bar"]
keras.Model(inputs, outputs)
<Functional name=functional_2, built=True>
In Keras 2, TF autograph is enabled by default on the call()
method of custom
layers. In Keras 3, it is not. This means you may have to use cond ops if you're using
control flow, or alternatively you can decorate your call()
method with @tf.function
.
You would encounter an error as follows:
OperatorNotAllowedInGraphError: Exception encountered when calling MyCustomLayer.call().
Using a symbolic [`tf.Tensor`](https://www.tensorflow.org/api_docs/python/tf/Tensor) as a Python `bool` is not allowed. You can attempt the
following resolutions to the problem: If you are running in Graph mode, use Eager
execution mode or decorate this function with @tf.function. If you are using AutoGraph,
you can try decorating this function with @tf.function. If that does not work, then you
may be using an unsupported feature or your source code may not be visible to AutoGraph.
Here is a [link for more information](https://github.com/tensorflow/tensorflow/blob/master/tensorflow/python/autograph/g3doc/ref
erence/limitations.md#access-to-source-code).
The following snippet of code will reproduce the above error:
class MyCustomLayer(keras.layers.Layer):
def call(self, inputs):
if tf.random.uniform(()) > 0.5:
return inputs * 2
else:
return inputs / 2
layer = MyCustomLayer()
data = np.random.uniform(size=[3, 3])
model = keras.models.Sequential([layer])
model.compile(optimizer="adam", loss="mse")
model.predict(data)
How to fix it: decorate your call()
method with @tf.function
class MyCustomLayer(keras.layers.Layer):
@tf.function()
def call(self, inputs):
if tf.random.uniform(()) > 0.5:
return inputs * 2
else:
return inputs / 2
layer = MyCustomLayer()
data = np.random.uniform(size=[3, 3])
model = keras.models.Sequential([layer])
model.compile(optimizer="adam", loss="mse")
model.predict(data)
1/1 ━━━━━━━━━━━━━━━━━━━━ 0s 43ms/step
array([[0.59727275, 1.9986179 , 1.5514829 ],
[0.56239295, 1.6529864 , 0.33085832],
[0.67086476, 1.5208522 , 1.99276 ]], dtype=float32)
KerasTensor
Using a TF op on a Keras tensor during functional model construction is disallowed: "A KerasTensor cannot be used as input to a TensorFlow function".
The error you would encounter would be as follows:
ValueError: A KerasTensor cannot be used as input to a TensorFlow function. A KerasTensor
is a symbolic placeholder for a shape and dtype, used when constructing Keras Functional
models or Keras Functions. You can only use it as input to a Keras layer or a Keras
operation (from the namespaces `keras.layers` and `keras.operations`).
The following snippet of code will reproduce the error:
input = keras.layers.Input([2, 2, 1])
tf.squeeze(input)
How to fix it: use an equivalent op from keras.ops
.
input = keras.layers.Input([2, 2, 1])
keras.ops.squeeze(input)
<KerasTensor shape=(None, 2, 2), dtype=float32, sparse=None, name=keras_tensor_6>
evaluate()
The evaluate()
method of a multi-output model no longer returns individual output
losses separately. Instead, you should utilize the metrics
argument in the compile()
method to keep track of these losses.
When dealing with multiple named outputs, such as output_a and output_b, the legacy
tf.keras
would include
The following snippet of code will reproduce the above behavior:
from keras import layers
# A functional model with multiple outputs
inputs = layers.Input(shape=(10,))
x1 = layers.Dense(5, activation='relu')(inputs)
x2 = layers.Dense(5, activation='relu')(x1)
output_1 = layers.Dense(5, activation='softmax', name="output_1")(x1)
output_2 = layers.Dense(5, activation='softmax', name="output_2")(x2)
model = keras.Model(inputs=inputs, outputs=[output_1, output_2])
model.compile(optimizer='adam', loss='categorical_crossentropy')
# dummy data
x_test = np.random.uniform(size=[10, 10])
y_test = np.random.uniform(size=[10, 5])
model.evaluate(x_test, y_test)
from keras import layers
# A functional model with multiple outputs
inputs = layers.Input(shape=(10,))
x1 = layers.Dense(5, activation="relu")(inputs)
x2 = layers.Dense(5, activation="relu")(x1)
output_1 = layers.Dense(5, activation="softmax", name="output_1")(x1)
output_2 = layers.Dense(5, activation="softmax", name="output_2")(x2)
# dummy data
x_test = np.random.uniform(size=[10, 10])
y_test = np.random.uniform(size=[10, 5])
multi_output_model = keras.Model(inputs=inputs, outputs=[output_1, output_2])
multi_output_model.compile(
optimizer="adam",
loss="categorical_crossentropy",
metrics=["categorical_crossentropy", "categorical_crossentropy"],
)
multi_output_model.evaluate(x_test, y_test)
1/1 ━━━━━━━━━━━━━━━━━━━━ 0s 112ms/step - loss: 4.0217 - output_1_categorical_crossentropy: 4.0217
[4.021683692932129, 4.021683692932129]
Setting a tf.Variable
as an attribute of a Keras 3 layer or model will not automatically
track the variable, unlike in Keras 2. The following snippet of code will show that the tf.Variables
are not being tracked.
class MyCustomLayer(keras.layers.Layer):
def __init__(self, units):
super().__init__()
self.units = units
def build(self, input_shape):
input_dim = input_shape[-1]
self.w = tf.Variable(initial_value=tf.zeros([input_dim, self.units]))
self.b = tf.Variable(initial_value=tf.zeros([self.units,]))
def call(self, inputs):
return keras.ops.matmul(inputs, self.w) + self.b
layer = MyCustomLayer(3)
data = np.random.uniform(size=[3, 3])
model = keras.models.Sequential([layer])
model.compile(optimizer="adam", loss="mse")
model.predict(data)
# The model does not have any trainable variables
for layer in model.layers:
print(layer.trainable_variables)
You will see the following warning:
UserWarning: The model does not have any trainable weights.
warnings.warn("The model does not have any trainable weights.")
How to fix it: use self.add_weight()
method or opt for a keras.Variable
instead. If you
are currently using tf.variable
, you can switch to keras.Variable
.
class MyCustomLayer(keras.layers.Layer):
def __init__(self, units):
super().__init__()
self.units = units
def build(self, input_shape):
input_dim = input_shape[-1]
self.w = self.add_weight(
shape=[input_dim, self.units],
initializer="zeros",
)
self.b = self.add_weight(
shape=[
self.units,
],
initializer="zeros",
)
def call(self, inputs):
return keras.ops.matmul(inputs, self.w) + self.b
layer = MyCustomLayer(3)
data = np.random.uniform(size=[3, 3])
model = keras.models.Sequential([layer])
model.compile(optimizer="adam", loss="mse")
model.predict(data)
# Verify that the variables are now being tracked
for layer in model.layers:
print(layer.trainable_variables)
1/1 ━━━━━━━━━━━━━━━━━━━━ 0s 33ms/step
[<KerasVariable shape=(3, 3), dtype=float32, path=sequential_2/my_custom_layer_1/variable>, <KerasVariable shape=(3,), dtype=float32, path=sequential_2/my_custom_layer_1/variable_1>]
None
entries in nested call()
argumentsNone
entries are not allowed as part of nested (e.g. list/tuples) tensor
arguments in Layer.call()
, nor as part of call()
's nested return values.
If the None
in the argument is intentional and serves a specific purpose,
ensure that the argument is optional and structure it as a separate parameter.
For example, consider defining the call
method with optional argument.
The following snippet of code will reproduce the error.
class CustomLayer(keras.layers.Layer):
def __init__(self):
super().__init__()
def call(self, inputs):
foo = inputs["foo"]
baz = inputs["bar"]["baz"]
if baz is not None:
return foo + baz
return foo
layer = CustomLayer()
inputs = {
"foo": keras.Input(shape=(1,), name="foo"),
"bar": {
"baz": None,
},
}
layer(inputs)
How to fix it:
Solution 1: Replace None
with a value, like this:
class CustomLayer(keras.layers.Layer):
def __init__(self):
super().__init__()
def call(self, inputs):
foo = inputs["foo"]
baz = inputs["bar"]["baz"]
return foo + baz
layer = CustomLayer()
inputs = {
"foo": keras.Input(shape=(1,), name="foo"),
"bar": {
"baz": keras.Input(shape=(1,), name="bar"),
},
}
layer(inputs)
<KerasTensor shape=(None, 1), dtype=float32, sparse=False, name=keras_tensor_14>
Solution 2: Define the call method with an optional argument. Here is an example of this fix:
class CustomLayer(keras.layers.Layer):
def __init__(self):
super().__init__()
def call(self, foo, baz=None):
if baz is not None:
return foo + baz
return foo
layer = CustomLayer()
foo = keras.Input(shape=(1,), name="foo")
baz = None
layer(foo, baz=baz)
<KerasTensor shape=(None, 1), dtype=float32, sparse=False, name=keras_tensor_15>
Keras 3 is significantly stricter than Keras 2 about when state (e.g. numerical weight variables) can be created. Keras 3 wants all state to be created before the model can be trained. This is a requirement for using JAX (whereas TensorFlow was very lenient about state creation timing).
Keras layers should create their state either in their constructor (__init__()
method) or in their build()
method.
They should avoid creating state in call()
.
If you ignore this recommendation and create state in call()
anyway (e.g. by calling a previously unbuilt layer), then Keras will attempt to build the layer automatically
by calling the call()
method on symbolic inputs before training.
However, this attempt at automatic state creation may fail in certain cases.
This will cause an error that looks like like this:
Layer 'frame_position_embedding' looks like it has unbuilt state,
but Keras is not able to trace the layer `call()` in order to build it automatically.
Possible causes:
1. The `call()` method of your layer may be crashing.
Try to `__call__()` the layer eagerly on some test input first to see if it works.
E.g. `x = np.random.random((3, 4)); y = layer(x)`
2. If the `call()` method is correct, then you may need to implement
the `def build(self, input_shape)` method on your layer.
It should create all variables used by the layer
(e.g. by calling `layer.build()` on all its children layers).
You could reproduce this error with the following layer, when used with the JAX backend:
class PositionalEmbedding(keras.layers.Layer):
def __init__(self, sequence_length, output_dim, **kwargs):
super().__init__(**kwargs)
self.position_embeddings = layers.Embedding(
input_dim=sequence_length, output_dim=output_dim
)
self.sequence_length = sequence_length
self.output_dim = output_dim
def call(self, inputs):
inputs = keras.ops.cast(inputs, self.compute_dtype)
length = keras.ops.shape(inputs)[1]
positions = keras.ops.arange(start=0, stop=length, step=1)
embedded_positions = self.position_embeddings(positions)
return inputs + embedded_positions
How to fix it: Do exactly what the error message asks. First, try to run the layer eagerly
to see if the call()
method is in fact correct (note: if it was working in Keras 2, then it is correct
and does not need to be changed). If it is indeed correct, then you should implement a build(self, input_shape)
method that creates all of the layer's state, including the state of sublayers. Here's the fix as applied for the layer above
(note the build()
method):
class PositionalEmbedding(keras.layers.Layer):
def __init__(self, sequence_length, output_dim, **kwargs):
super().__init__(**kwargs)
self.position_embeddings = layers.Embedding(
input_dim=sequence_length, output_dim=output_dim
)
self.sequence_length = sequence_length
self.output_dim = output_dim
def build(self, input_shape):
self.position_embeddings.build(input_shape)
def call(self, inputs):
inputs = keras.ops.cast(inputs, self.compute_dtype)
length = keras.ops.shape(inputs)[1]
positions = keras.ops.arange(start=0, stop=length, step=1)
embedded_positions = self.position_embeddings(positions)
return inputs + embedded_positions
A small number of legacy features with very low usage were removed from Keras 3 as a cleanup measure:
keras.layers.ThresholdedReLU
is removed. Instead, you can simply use the ReLU
layer
with the argument threshold
.Layer.add_loss()
: Symbolic add_loss()
is removed (you can still use
add_loss()
inside the call()
method of a layer/model).LocallyConnected1D
, LocallyConnected2D
are removed due to very low usage. To
use locally connected layers, copy the layer implementation into your own codebase.keras.layers.experimental.RandomFourierFeatures
is removed due to very low usage.
To use it, copy the layer implementation into your own codebase.metrics
, dynamic
are removed. metrics
is still
available on the Model
class.constants
and time_major
arguments in RNN layers are removed.
The constants
argument was a remnant of Theano and had very low usage. The time_major
argument also had very low usage.reset_metrics
argument: The reset_metrics
argument is removed from model.*_on_batch()
methods. This argument had very low usage.keras.constraints.RadialConstraint
object is removed. This object had very low usage.Keras 3 code with the TensorFlow backend will work with native TensorFlow APIs. However, if you want your code to be backend-agnostic, you will need to:
tf.*
API calls with their equivalent Keras APIs.train_step
/test_step
methods to a multi-framework
implementation.keras.random
ops correctly in your layers.Let's go over each point in detail.
In many cases, this is the only thing you need to do to start being able to run
your custom layers and metrics with JAX and PyTorch:
replace any tf.*
, tf.math*
, tf.linalg.*
, etc. with keras.ops.*
. Most TF ops
should be consistent with Keras 3. If the names different, they will be
highlighted in this guide.
Keras implements the NumPy API as part of keras.ops
.
The table below only lists a small subset of TensorFlow and Keras ops; ops not listed
are usually named the same in both frameworks (e.g. reshape
, matmul
, cast
, etc.)
train_step()
methodsYour models may include a custom train_step()
or test_step()
method, which rely
on TensorFlow-only APIs – for instance, your train_step()
method may leverage TensorFlow's tf.GradientTape
.
To convert such models to run on JAX or PyTorch, you will have a write a different train_step()
implementation
for each backend you want to support.
In some cases, you might be able to simply override the Model.compute_loss()
method and make it fully backend-agnostic,
instead of overriding train_step()
. Here's an example of a layer with a custom compute_loss()
method which works
across JAX, TensorFlow, and PyTorch:
class MyModel(keras.Model):
def compute_loss(self, x=None, y=None, y_pred=None, sample_weight=None):
loss = keras.ops.sum(keras.losses.mean_squared_error(y, y_pred, sample_weight))
return loss
If you need to modify the optimization mechanism itself, beyond the loss computation,
then you will need to override train_step()
, and implement one train_step
method per backend, like below.
See the following guides for details on how each backend should be handled:
fit()
with JAXfit()
with TensorFlowfit()
with PyTorchclass MyModel(keras.Model):
def train_step(self, *args, **kwargs):
if keras.backend.backend() == "jax":
return self._jax_train_step(*args, **kwargs)
elif keras.backend.backend() == "tensorflow":
return self._tensorflow_train_step(*args, **kwargs)
elif keras.backend.backend() == "torch":
return self._torch_train_step(*args, **kwargs)
def _jax_train_step(self, state, data):
pass # See guide: keras.io/guides/custom_train_step_in_jax/
def _tensorflow_train_step(self, data):
pass # See guide: keras.io/guides/custom_train_step_in_tensorflow/
def _torch_train_step(self, data):
pass # See guide: keras.io/guides/custom_train_step_in_torch/
Keras 3 has a new keras.random
namespace, containing:
These operations are stateless, which means that if you pass a seed
argument, they will return the same result every time. Like this:
print(keras.random.normal(shape=(), seed=123))
print(keras.random.normal(shape=(), seed=123))
tf.Tensor(0.7832616, shape=(), dtype=float32)
tf.Tensor(0.7832616, shape=(), dtype=float32)
Crucially, this differs from the behavior of stateful tf.random
ops:
print(tf.random.normal(shape=(), seed=123))
print(tf.random.normal(shape=(), seed=123))
tf.Tensor(2.4435377, shape=(), dtype=float32)
tf.Tensor(-0.6386405, shape=(), dtype=float32)
When you write a RNG-using layer, such as a custom dropout layer, you are going to want to use a different seed value at layer call. However, you cannot just increment a Python integer and pass it, because while this would work fine when executed eagerly, it would not work as expected when using compilation (which is available with JAX, TensorFlow, and PyTorch). When compiling the layer, the first Python integer seed value seen by the layer would be hardcoded into the compiled graph.
To address this, you should pass as the seed
argument an instance of a
stateful keras.random.SeedGenerator
object, like this:
seed_generator = keras.random.SeedGenerator(1337)
print(keras.random.normal(shape=(), seed=seed_generator))
print(keras.random.normal(shape=(), seed=seed_generator))
tf.Tensor(0.6077996, shape=(), dtype=float32)
tf.Tensor(0.8211102, shape=(), dtype=float32)
So when writing a RNG using layer, you would use the following pattern:
class RandomNoiseLayer(keras.layers.Layer):
def __init__(self, noise_rate, **kwargs):
super().__init__(**kwargs)
self.noise_rate = noise_rate
self.seed_generator = keras.random.SeedGenerator(1337)
def call(self, inputs):
noise = keras.random.uniform(
minval=0, maxval=self.noise_rate, seed=self.seed_generator
)
return inputs + noise
Such a layer is safe to use in any setting – in eager execution or in a compiled model. Each layer call will be using a different seed value, as expected.